-x^2+4x+429=0

Solution for -x^2+4x+429=0 equation:

-x^2+4x+429=0

We add all the numbers together, and all the variables

-1x^2+4x+429=0

a = -1; b = 4; c = +429;
Δ = b2-4ac
Δ = 42-4·(-1)·429
Δ = 1732
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1732}=\sqrt{4*433}=\sqrt{4}*\sqrt{433}=2\sqrt{433}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{433}}{2*-1}=\frac{-4-2\sqrt{433}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{433}}{2*-1}=\frac{-4+2\sqrt{433}}{-2}
$